回答編集履歴
1
追記
answer
CHANGED
@@ -35,4 +35,35 @@
|
|
35
35
|
}
|
36
36
|
|
37
37
|
```
|
38
|
-
ではないですか?
|
38
|
+
ではないですか?
|
39
|
+
|
40
|
+
# 追記
|
41
|
+
とりあえず地道に冗長に処理してみてください
|
42
|
+
|
43
|
+
```javascript
|
44
|
+
var obj_0={
|
45
|
+
hoge:[
|
46
|
+
{1:["a","b","c","d"]},
|
47
|
+
{2:["c","d","a","d"]}
|
48
|
+
]
|
49
|
+
};
|
50
|
+
var obj_1={};
|
51
|
+
for(var i=0;i<obj_0.hoge.length;i++){
|
52
|
+
for(var j in obj_0.hoge[i]){
|
53
|
+
var obj_2=obj_0.hoge[i][j].filter(function (x, y, z){return z.indexOf(x) === y;});
|
54
|
+
var obj_3=obj_0.hoge[i][j];
|
55
|
+
for(var k=0;k<obj_2.length;k++){
|
56
|
+
if(typeof obj_1[obj_2[k]]=="undefined"){obj_1[obj_2[k]]={};}
|
57
|
+
for(var l=0;l<obj_3.length;l++){
|
58
|
+
if(obj_2[k]==obj_3[l]){continue;}
|
59
|
+
if(typeof obj_1[obj_2[k]][obj_3[l]]=="undefined"){
|
60
|
+
obj_1[obj_2[k]][obj_3[l]]=1;
|
61
|
+
}else{
|
62
|
+
obj_1[obj_2[k]][obj_3[l]]++;
|
63
|
+
}
|
64
|
+
}
|
65
|
+
}
|
66
|
+
}
|
67
|
+
}
|
68
|
+
console.log(obj_1);
|
69
|
+
```
|