回答編集履歴
2
コード追記
test
CHANGED
@@ -17,3 +17,17 @@
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17
17
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HAVING
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18
18
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Count(projects.id) = 2;
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19
19
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```
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20
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+
あるいは、EXISTS を使って、
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21
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+
```sql
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22
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+
SELECT projects.id, projects.name
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23
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FROM projects
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24
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WHERE
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25
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EXISTS (
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SELECT * FROM projects_skills
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27
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WHERE projects.id = projects_skills.project_id and projects_skills.skill_id = 2
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) AND
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EXISTS (
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SELECT * FROM projects_skills
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WHERE projects.id = projects_skills.project_id and projects_skills.skill_id = 3
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+
);
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33
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+
```
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1
コード修正
test
CHANGED
@@ -5,14 +5,10 @@
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5
5
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```sql
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6
6
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SELECT
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7
7
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projects.id,
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8
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-
projects.name
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8
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+
projects.name
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9
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-
Count(projects.id) AS idのカウント
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10
9
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FROM
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11
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-
skills
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12
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-
RIGHT JOIN (
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-
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10
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+
projects RIGHT JOIN projects_skills
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14
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-
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11
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+
ON projects.id = projects_skills.project_id
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15
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-
) ON skills.id = projects_skills.skill_id
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16
12
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WHERE
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13
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projects_skills.skill_id In (2, 3)
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18
14
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GROUP BY
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