回答編集履歴

1

element\.addClass\('active'\)

2016/11/09 06:22

投稿

think49
think49

スコア18166

test CHANGED
@@ -68,17 +68,17 @@
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  'use strict';
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- var cards = jQuery('#stage .card').filter(function (i, element) {
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+ jQuery('.card:not(.active)').each(function (i, element) {
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- return jQuery(element).data('no') % 10 === 2;
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+ element = jQuery(element);
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-
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- });
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- cards.each(function (i, element) {
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+ if (element.data('no') % 10 === 2) {
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- console.log(element);
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+ element.addClass('active');
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+
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+ }
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  });
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