回答編集履歴
5
変更
test
CHANGED
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@@ -1,4 +1,18 @@
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1
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-
NOT EXIST版です。
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1
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+
NOT EXIST版です。訂正です。
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2
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3
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4
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5
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+
```sql
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6
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7
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INSERT INTO RS (code,name) SELECT code,name FROM `ALL`
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8
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9
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WHERE NOT EXISTS (SELECT 1 FROM RS WHERE code=`ALL`.code);
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10
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11
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```
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12
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13
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14
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15
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+
NOT IN 版です。
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2
16
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3
17
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4
18
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4
変更
test
CHANGED
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@@ -24,7 +24,7 @@
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24
24
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25
25
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26
26
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27
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-
nameが変更される場合は
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27
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+
nameが変更される場合は、但し（codeがprimary key）
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28
28
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29
29
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```
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30
30
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3
変更
test
CHANGED
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@@ -17,3 +17,19 @@
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17
17
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INSERT INTO RS(code,name) SELECT t1.code,t1.name FROM `ALL` t1 LEFT JOIN RS t2 USING(code) WHERE t2.code IS NULL;
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18
18
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19
19
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```
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20
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+
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21
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+
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22
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+
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23
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> ALLが最新情報のため、RSを最新情報に更新したいと思います
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24
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25
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+
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26
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+
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27
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+
nameが変更される場合は
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28
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+
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29
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```
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30
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+
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31
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INSERT INTO RS (code,name) SELECT t.code , t.name FROM `ALL` AS t
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32
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+
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33
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ON DUPLICATE KEY UPDATE RS.name = t.name
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34
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+
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35
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+
```
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2
変更
test
CHANGED
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@@ -4,7 +4,7 @@
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4
4
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5
5
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```sql
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6
6
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7
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-
INSERT INTO RS(code,name) SELECT code,name FROM ALL WHERE ALL.code NOT IN (SELECT code FROM RS);
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7
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+
INSERT INTO RS(code,name) SELECT code,name FROM `ALL` WHERE `ALL`.code NOT IN (SELECT code FROM RS);
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8
8
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9
9
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```
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10
10
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@@ -14,6 +14,6 @@
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14
14
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15
15
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```sql
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16
16
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17
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-
INSERT INTO RS(code,name) SELECT t1.code,t1.name FROM ALL t1 LEFT JOIN RS t2 USING(code) WHERE t2.code IS NULL;
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17
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+
INSERT INTO RS(code,name) SELECT t1.code,t1.name FROM `ALL` t1 LEFT JOIN RS t2 USING(code) WHERE t2.code IS NULL;
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18
18
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19
19
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```
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1
追加
test
CHANGED
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@@ -7,3 +7,13 @@
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7
7
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INSERT INTO RS(code,name) SELECT code,name FROM ALL WHERE ALL.code NOT IN (SELECT code FROM RS);
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8
8
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9
9
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```
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10
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+
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11
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12
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13
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+
JOIN でも可能
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14
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+
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15
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+
```sql
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16
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+
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17
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+
INSERT INTO RS(code,name) SELECT t1.code,t1.name FROM ALL t1 LEFT JOIN RS t2 USING(code) WHERE t2.code IS NULL;
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18
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+
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19
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+
```
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