回答編集履歴
2
2
answer
CHANGED
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@@ -25,4 +25,5 @@
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25
25
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'batu'=>$a['batu'],
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26
26
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);
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27
27
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}
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28
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-
```
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28
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+
```
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29
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+
//あ、こっちはSQLそのままって前提です。
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1
1
answer
CHANGED
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@@ -1,4 +1,28 @@
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1
1
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SQLですませていいならこんなかんじ?
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2
2
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```PHP
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3
3
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$sth = $dbh->prepare("SELECT day_id, sum(maru) as maru, sum(batu) as batu FROM data WHERE num1 = ? AND num2 = ? group by day_id");
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4
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+
```
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5
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+
--- 追加 ---
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6
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+
//かぶったのでコードの方も(^_^;
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7
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+
```PHP
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8
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+
$Data = array();
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9
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+
while($row = $sth->fetch(PDO::FETCH_ASSOC)){
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10
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+
$id = $row['day_id'];
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11
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+
if (!isset($Data[$id]) {
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12
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+
$Data[$id] = array();
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13
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+
$Data[$id]['maru'] = 0;
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14
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+
$Data[$id]['batu'] = 0;
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15
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+
}
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16
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+
$Data[$id]['maru'] += $row['maru'];
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17
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+
$Data[$id]['batu'] += $row['batu'];
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18
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+
}
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19
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+
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20
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+
$Data2 = array();
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21
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+
foreach ($Data as $k=>$a) {
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22
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+
$Data2[] = array(
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23
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+
'day_id'=>$k,
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24
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+
'maru'=>$a['maru'],
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25
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+
'batu'=>$a['batu'],
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26
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+
);
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27
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+
}
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4
28
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```
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