回答編集履歴
1
追記
test
CHANGED
@@ -3,3 +3,53 @@
|
|
3
3
|
たとえばdata1とdata2を集約するとして、data1にdata2のhoursを加算して
|
4
4
|
|
5
5
|
data2を削除する?(表示しない)?
|
6
|
+
|
7
|
+
|
8
|
+
|
9
|
+
#追記
|
10
|
+
|
11
|
+
ベタな処理ですが各データのdateもidも文字列なので連結してキーにしてしまえばよいかも
|
12
|
+
|
13
|
+
```javascript
|
14
|
+
|
15
|
+
var data ={
|
16
|
+
|
17
|
+
"data1":{"date":"2016-09-01","id": "ID1","hours":"1"},
|
18
|
+
|
19
|
+
"data2":{"date":"2016-09-01","id": "ID1","hours":"2"},
|
20
|
+
|
21
|
+
"data3":{"date":"2016-09-01","id": "ID2","hours":"3"},
|
22
|
+
|
23
|
+
"data4":{"date":"2016-09-01","id": "ID2","hours":"4"},
|
24
|
+
|
25
|
+
"data5":{"date":"2016-09-02","id": "ID1","hours":"5"},
|
26
|
+
|
27
|
+
"data6":{"date":"2016-09-02","id": "ID2","hours":"6"},
|
28
|
+
|
29
|
+
};
|
30
|
+
|
31
|
+
var tmp={};
|
32
|
+
|
33
|
+
for(key in data){
|
34
|
+
|
35
|
+
var n=data[key]["date"]+":"+data[key]["id"];
|
36
|
+
|
37
|
+
if(typeof tmp[n]=="undefined"){
|
38
|
+
|
39
|
+
tmp[n]=parseInt(data[key]["hours"]);
|
40
|
+
|
41
|
+
}else{
|
42
|
+
|
43
|
+
tmp[n]+=parseInt(data[key]["hours"]);
|
44
|
+
|
45
|
+
}
|
46
|
+
|
47
|
+
}
|
48
|
+
|
49
|
+
for(key in tmp){
|
50
|
+
|
51
|
+
console.log(key+"="+tmp[key]);
|
52
|
+
|
53
|
+
}
|
54
|
+
|
55
|
+
```
|