回答編集履歴
2
そのままにする部分が抜けていたので追加
answer
CHANGED
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@@ -41,10 +41,17 @@
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41
41
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, A.userID
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42
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) T2
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SET
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44
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+
T1.ID = MID(T1.ID, 1, 1)
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44
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-
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45
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+ MID('abcdefghijklmnopqrstuvwxyz', T2.cnt, 1)
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46
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+ MID(T1.ID, 3, 1)
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WHERE T1.ID = T2.ID
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AND T1.userID = T2.userID
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47
49
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48
50
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```
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49
51
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50
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-
UPDATEのFROM副問い合わせはすっかりSQLServerのノリで書いてましたf(^-^;
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52
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+
UPDATEのFROM副問い合わせはすっかりSQLServerのノリで書いてましたf(^-^;
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53
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+
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54
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---
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55
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+
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56
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追記
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57
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+
そのまま残すべきところを忘れていたので追加しました
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1
指摘を受けて修正
answer
CHANGED
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@@ -16,4 +16,35 @@
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16
16
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WHERE sampleTable.ID = C.ID
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AND sampleTable.userID = C.userID
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-
```
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19
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+
```
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+
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21
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+
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22
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---
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23
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+
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24
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+
KotoriMaturiさんの指摘を受けて修正しました
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25
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+
(GROUP BYもぬけてましたし)
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+
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27
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+
```SQL
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28
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UPDATE
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+
sampleTable T1
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, (
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SELECT
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A.ID
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, A.userID
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, count(*) + 1 AS cnt
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35
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FROM sampleTable A
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JOIN sampleTable B
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ON A.ID = B.ID
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AND A.userID > B.userID
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GROUP BY
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40
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A.ID
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41
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, A.userID
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42
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) T2
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43
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SET
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T1.ID = MID('abcdefghijklmnopqrstuvwxyz', T2.cnt, 1)
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WHERE T1.ID = T2.ID
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46
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AND T1.userID = T2.userID
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47
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+
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48
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+
```
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49
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+
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50
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+
UPDATEのFROM副問い合わせはすっかりSQLServerのノリで書いてましたf(^-^;
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