回答編集履歴
2
追記
test
CHANGED
@@ -36,4 +36,60 @@
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```
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###追記
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これで試してみてください。
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input.csv
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```CSV
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1601,2016/08/04,001,001
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1017,2016/08/04,002,025
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1058,2016/08/04,103,001
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1358,2016/08/04,500,002
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0910,2016/08/04,500,""
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```
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input_list.csv
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```CSV
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001,りんご支店
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002,バナナ支店
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025,キウイ支店
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103,みかん支店
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500,メロン支店
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```
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convert.ps1
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```PowerShell
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$dic = @{}
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Import-Csv .\input_list.csv -Header ID, Name |
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% {$dic[$_.ID] = $_.Name}
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Import-Csv .\input.csv -Header No., day, ID1, ID2 |
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Select-Object No., day, @{Name="ID1"; Expression={$dic[$_.ID1.PadLeft(3, "0")]}}, @{Name="ID2"; Expression={$dic[$_.ID2.PadLeft(3, "0")]}} |
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Export-Csv .\OUTPUTData.csv -Encoding Default -NoTypeInformation -Force
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```
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1
追記
test
CHANGED
@@ -11,3 +11,29 @@
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%{ $_.END.PadLeft(3,"0")}
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```
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###追記
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たとえばこれを
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```PowerShell
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Get-Content C:\work\INPUT.csv | ConvertFrom-Csv -Header No.,day,ID1,ID2 |
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%{ $_.ID1.PadLeft(3,"0")} |
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%{ $_.ID2.PadLeft(3,"0")}
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```
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こう変えるとお望みの動作になりますか?
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```PowerShell
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Get-Content C:\work\INPUT.csv | ConvertFrom-Csv -Header No.,day,ID1,ID2 |
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Select-Object No., day, @{Name="ID1"; Expression={$_.ID1.PadLeft(3, "0")}}, @{Name="ID2"; Expression={$_.ID2.PadLeft(3, "0")}}
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```
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