回答編集履歴
2
指摘の修正
answer
CHANGED
@@ -2,5 +2,5 @@
|
|
2
2
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SELECT ID, COUNT(ID) AS CNT FROM TABLE
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3
3
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WHERE 回数=1
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4
4
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GROUP BY ID
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5
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-
HAVING COUNT(ID)
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5
|
+
HAVING COUNT(ID) = 1
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6
6
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```
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1
質問に沿った回答に修正
answer
CHANGED
@@ -1,3 +1,6 @@
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|
1
1
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```SQL
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2
|
-
SELECT
|
2
|
+
SELECT ID, COUNT(ID) AS CNT FROM TABLE
|
3
|
+
WHERE 回数=1
|
4
|
+
GROUP BY ID
|
5
|
+
HAVING COUNT(ID) > 1
|
3
6
|
```
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