回答編集履歴

2

指摘の修正

2016/04/27 06:28

投稿

ttyp03
ttyp03

スコア16998

test CHANGED
@@ -6,6 +6,6 @@
6
6
 
7
7
  GROUP BY ID
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8
 
9
- HAVING COUNT(ID) > 1
9
+ HAVING COUNT(ID) = 1
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10
 
11
11
  ```

1

質問に沿った回答に修正

2016/04/27 06:28

投稿

ttyp03
ttyp03

スコア16998

test CHANGED
@@ -1,5 +1,11 @@
1
1
  ```SQL
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2
 
3
- SELECT DISTINCT * FROM テーブル WHERE 回数=1
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+ SELECT ID, COUNT(ID) AS CNT FROM TABLE
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+
5
+ WHERE 回数=1
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+
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+ GROUP BY ID
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+
9
+ HAVING COUNT(ID) > 1
4
10
 
5
11
  ```