回答編集履歴
2
調整
answer
CHANGED
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@@ -30,4 +30,22 @@
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30
30
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GROUP BY
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31
31
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week
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32
32
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with rollup
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33
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-
```
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33
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+
```
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34
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+
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35
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+
平日の集計だけ
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36
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```SQL
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37
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SELECT * FROM(
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38
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SELECT
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39
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case when WEEKDAY(created_at) BETWEEN 1 AND 5 then 1 else 0 end as heijitu,
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40
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WEEKDAY(created_at) as week,
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41
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SUM(fee) AS total_fee
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42
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FROM
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users
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44
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GROUP BY
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45
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heijitu,week with rollup
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46
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having week is not null or week is null and heijitu=1
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47
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) as sub
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48
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order by week is null,week
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49
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+
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50
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```
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51
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※平日だけ集計して行を増やすのは合理的ではないのであまりおすすめできません
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1
chousei
answer
CHANGED
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@@ -1,7 +1,33 @@
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1
1
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```SQL
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2
2
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SELECT
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3
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-
SUM(
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3
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+
SUM(fee) AS total_fee
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4
4
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FROM
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5
5
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users
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6
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-
WHERE WEEKDAY(
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6
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+
WHERE WEEKDAY(created_at) BETWEEN 1 AND 5
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7
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```
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8
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9
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# 追記
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10
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平日のそれぞれの売上と、その集計
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11
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（土日どうする？）
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12
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```SQL
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13
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create table users(id int primary key,fee int,created_at date);
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14
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insert into users values
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15
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(1,100,'2021-10-01'),
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(2,150,'2021-10-01'),
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(3,200,'2021-10-02'),
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(4,300,'2021-10-03'),
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19
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(5,120,'2021-10-04'),
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20
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(6,130,'2021-10-05'),
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21
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(7,400,'2021-10-05');
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22
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/*適当なデータ*/
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23
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24
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SELECT
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25
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WEEKDAY(created_at) as week,
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26
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+
SUM(fee) AS total_fee
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27
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FROM
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28
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users
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29
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WHERE WEEKDAY(created_at) BETWEEN 1 AND 5
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30
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GROUP BY
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31
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+
week
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32
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+
with rollup
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7
33
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```
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