回答編集履歴
3
体裁
test
CHANGED
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@@ -80,7 +80,7 @@
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80
80
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81
81
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, date
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82
82
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83
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-
, case when first_value(id) over(partition by user_id order by date
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83
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+
, case when first_value(id) over(partition by user_id order by date) = id
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84
84
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85
85
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then 1 else 0 end as 初登場
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86
86
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2
スキーマ定義を他の人の回答にあわせる
test
CHANGED
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@@ -14,13 +14,13 @@
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14
14
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15
15
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, user_id
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16
16
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17
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-
, date
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17
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+
, date
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18
18
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19
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-
, case when first_value(id) over(partition by user_id order by date
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19
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+
, case when first_value(id) over(partition by user_id order by date, id) = id
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20
20
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21
21
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then 1 else 0 end as 初登場
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22
22
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23
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-
from
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23
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+
from tx
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24
24
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25
25
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order by id
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26
26
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@@ -32,7 +32,7 @@
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32
32
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33
33
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34
34
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35
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-
| id | user_id | date
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35
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+
| id | user_id | date | 初登場 |
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36
36
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37
37
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| :--- | :------ | :--------- | :----- |
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38
38
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@@ -70,7 +70,7 @@
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70
70
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71
71
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```sql
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72
72
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73
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-
with sub1
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|
73
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+
with sub1 as
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74
74
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75
75
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(
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76
76
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@@ -78,21 +78,21 @@
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78
78
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79
79
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user_id
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80
80
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81
|
-
, date
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81
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+
, date
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82
82
|
|
|
83
|
-
, case when first_value(id) over(partition by user_id order by date
|
|
83
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+
, case when first_value(id) over(partition by user_id order by date, id) = id
|
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84
84
|
|
|
85
|
-
then 1 else 0 end
|
|
85
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+
then 1 else 0 end as 初登場
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86
86
|
|
|
87
|
-
from
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|
87
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+
from tx
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88
88
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|
|
89
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-
), sub2
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|
89
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+
), sub2 as
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90
90
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91
91
|
(
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92
92
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93
93
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select
|
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94
94
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|
|
95
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-
date
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95
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+
date
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96
96
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97
97
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, count(distinct user_id) as 日別UU
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98
98
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@@ -100,7 +100,7 @@
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100
100
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101
101
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from sub1
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102
102
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|
|
103
|
-
group by date
|
|
103
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+
group by date
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104
104
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105
105
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)
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106
106
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|
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@@ -108,14 +108,14 @@
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108
108
|
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|
109
109
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select
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110
110
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111
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-
date
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111
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+
date
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112
112
|
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113
113
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, 日別UU
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|
114
114
|
|
|
115
|
-
, sum(通算UU) over(order by date
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|
115
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+
, sum(通算UU) over(order by date) as 通算UU
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|
116
116
|
|
|
117
117
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from sub2
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118
118
|
|
|
119
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-
order by date
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|
119
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+
order by date
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120
120
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121
121
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```
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1
要約変更
test
CHANGED
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@@ -1,4 +1,4 @@
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1
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-
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1
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+
結合や相関サブクエリを使わずにwindow関数のみで実現する方法を紹介します。
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2
2
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3
3
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4
4
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