回答編集履歴
5
修正
answer
CHANGED
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@@ -3,14 +3,14 @@
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3
3
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```js
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4
4
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const src = "特に山梨県の梨はみずみずしくて美味い";
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5
5
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6
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-
const dst = src.replaceAll(/山梨県|梨/
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6
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+
const dst = src.replaceAll(/山梨県|梨/gu, a => a === "梨" ? "りんご" : a);
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7
7
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console.log(dst);
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8
8
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```
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9
9
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10
10
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例えば「山梨県」の他に「二十世紀梨」を対象にするのであれば次のように書き換えます。
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11
11
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12
12
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```js
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13
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-
const dst = src.replaceAll(/山梨県|二十世紀梨|梨/
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13
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+
const dst = src.replaceAll(/山梨県|二十世紀梨|梨/gu, a => a === "梨" ? "りんご" : a);
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14
14
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```
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15
15
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16
16
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以上を関数化すると次のようになります。
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@@ -22,10 +22,18 @@
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22
22
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23
23
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const f = (src, target, ignore, replacement) => {
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24
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const searchValue = ignore.concat(target).map(escapeRegularExpression).join("|");
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25
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-
const regExp = new RegExp(searchValue, "
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25
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+
const regExp = new RegExp(searchValue, "gu");
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26
26
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return src.replace(regExp, a => a === target ? replacement : a);
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};
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28
28
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29
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const dst = f("特に山梨県の梨はみずみずしくて美味い", "梨", ["山梨県"], "りんご");
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30
30
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console.log(dst);
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31
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+
```
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32
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+
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33
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+
target や ignore にメタ文字が含まれておらず、無視する単語が一つということがどちらも保証されているなら、次のように簡単に書いてもいいでしょう。
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34
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+
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35
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+
```js
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36
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+
const f = (src, target, ignore, replacement) => {
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37
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return src.replace(new RegExp(`${ignore}|${target}`, "gu"), a => a === target ? replacement : a);
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38
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+
};
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31
39
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```
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4
リファクタリング
answer
CHANGED
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@@ -21,7 +21,7 @@
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21
21
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};
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22
22
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23
23
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const f = (src, target, ignore, replacement) => {
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24
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-
const searchValue = ignore.concat(target).map(
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24
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+
const searchValue = ignore.concat(target).map(escapeRegularExpression).join("|");
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25
25
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const regExp = new RegExp(searchValue, "g");
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26
26
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return src.replace(regExp, a => a === target ? replacement : a);
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27
27
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};
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3
リファクタリング
answer
CHANGED
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@@ -21,8 +21,7 @@
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21
21
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};
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22
22
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23
23
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const f = (src, target, ignore, replacement) => {
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24
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-
const targetValue = escapeRegularExpression(target);
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25
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-
const searchValue = ignore.
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24
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+
const searchValue = ignore.concat(target).map(a => escapeRegularExpression(a)).join("|");
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26
25
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const regExp = new RegExp(searchValue, "g");
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27
26
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return src.replace(regExp, a => a === target ? replacement : a);
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28
27
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};
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2
修正
answer
CHANGED
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@@ -24,7 +24,7 @@
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24
24
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const targetValue = escapeRegularExpression(target);
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25
25
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const searchValue = ignore.reduce((previousValue, currentValue) => `${escapeRegularExpression(currentValue)}|${previousValue}`, targetValue);
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26
26
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const regExp = new RegExp(searchValue, "g");
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27
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-
return src.replace(regExp, a => a ===
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27
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+
return src.replace(regExp, a => a === target ? replacement : a);
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28
28
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};
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29
29
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30
30
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const dst = f("特に山梨県の梨はみずみずしくて美味い", "梨", ["山梨県"], "りんご");
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1
追記
answer
CHANGED
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@@ -11,4 +11,22 @@
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11
11
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12
12
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```js
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13
13
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const dst = src.replaceAll(/山梨県|二十世紀梨|梨/g, a => a === "梨" ? "りんご" : a);
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14
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+
```
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15
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+
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16
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+
以上を関数化すると次のようになります。
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17
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+
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18
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+
```js
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19
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const escapeRegularExpression = re => {
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20
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return re.replace(/[\^$*+?.(){[|]/g, a => `\${a}`);
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21
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};
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22
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+
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23
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+
const f = (src, target, ignore, replacement) => {
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24
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const targetValue = escapeRegularExpression(target);
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25
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+
const searchValue = ignore.reduce((previousValue, currentValue) => `${escapeRegularExpression(currentValue)}|${previousValue}`, targetValue);
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26
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+
const regExp = new RegExp(searchValue, "g");
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27
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+
return src.replace(regExp, a => a === targetValue ? replacement : a);
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28
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};
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29
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+
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30
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const dst = f("特に山梨県の梨はみずみずしくて美味い", "梨", ["山梨県"], "りんご");
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31
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+
console.log(dst);
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14
32
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```
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