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回答編集履歴

1

chousei

2021/07/30 02:48

投稿

yambejp
yambejp

スコア117921

answer CHANGED
@@ -1,4 +1,16 @@
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  ```SQL
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+ create table tbl1(ID varchar(10),code varchar(10));
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+ insert into tbl1 values
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+ ('AAA','aaa111'),
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+ ('AAA','bbb111'),
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+ ('AAA','aaa111'),
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+ ('BBB','aaa111');
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+
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+ create table tbl2(ID varchar(10),mail varchar(10));
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+ insert into tbl2 values
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+ ('AAA',' aaa@'),
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+ ('BBB',' bbb@');
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+
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  select * from(
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  select ID,code,count(*)as cnt from tbl1
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  where code='aaa111'