回答編集履歴
1
コード修正
answer
CHANGED
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@@ -5,7 +5,6 @@
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5
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```typescript
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6
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const data = ['logo.png','search.png','stock.png'] //本当は画像データを想定した文字列
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7
7
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8
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-
type keyType = 'logo' | 'search';
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interface objType {
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'logo' : string,
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'search' : string
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@@ -19,16 +18,9 @@
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data.map((name: string) => {
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const keyN = name.split(".")[0];
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if (keyN !== 'logo' && keyN !== 'search' ) return;
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-
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const imgName: keyType = keyN;
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if(imgName === 'logo' || 'search') {
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nameObj[
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nameObj[keyN] = name;
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}
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return;
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});
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-
console.log(nameObj);
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-
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-
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```
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