回答編集履歴
1
chousei
answer
CHANGED
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@@ -1,3 +1,15 @@
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1
1
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```javascript
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2
2
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ary=ary.map(x=>x.map(Number));
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3
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+
```
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4
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+
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5
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+
# 任意の多次元
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6
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```javascript
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7
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const numb=a=>a instanceof(Array)?a.map(x=>numb(x)):Number(a);
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8
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let ary = [
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9
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[ '1','2','3'],
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10
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[ '4',['5','6'],['7',['8',['9']]]],
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11
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[ 'a', 'b', ['c','d']],
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12
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];
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13
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ary=numb(ary);
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14
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console.log(ary);
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3
15
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```
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