回答編集履歴
1
補足にあわせて、サンプルコードを変更
test
CHANGED
@@ -127,3 +127,127 @@
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</html>
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```
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--
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追記 (2016.03.05 21:45)
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興味を持ったので、サンプルを Google Spreadsheet から、住所を取り出すようにしてみました。
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KEY の部分は、Google Spreadsheet の ID です。
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```HTML
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<!DOCTYPE HTML>
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<html lang="ja">
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<head>
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<meta charset="UTF-8">
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<title>Google Maps テスト</title>
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<style type="text/css">
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#googlemap {
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width: 700px;
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height: 700px;
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margin: 0 auto;
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}
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</style>
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</head>
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<body>
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<div id="googlemap"></div>
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
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<script type="text/javascript">
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var googleSheetUrl = "https://spreadsheets.google.com/feeds/cells/[KEY]/od6/public/basic?alt=json";
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var map;
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var marker = [];
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function viewMap() {
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var latlng = new google.maps.LatLng({lat: 35.693, lng: 139.735});
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map = new google.maps.Map(document.getElementById('googlemap'), {
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center: latlng,
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zoom: 13
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});
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var geocoder = new google.maps.Geocoder();
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$.get({
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url: googleSheetUrl,
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cache: false,
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dataType: "jsonp",
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success : function(data, status){
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$.each(data.feed.entry, function(i, item){
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geocoder.geocode(
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{ address: item.content.$t },
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function(result, status){
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if(status==google.maps.GeocoderStatus.OK){
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marker[i] = new google.maps.Marker({
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position: result[0].geometry.location,
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map: map
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});
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}
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}
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);
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});
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}
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});
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}
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</script>
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<script src="https://maps.googleapis.com/maps/api/js?callback=viewMap"></script>
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</body>
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</html>
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```
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