回答編集履歴
3
追記
answer
CHANGED
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@@ -9,4 +9,10 @@
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9
9
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```SQL
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10
10
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select distinct user from X t
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11
11
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where (select count(*) from X where user=t.user and attr in ('pretty', 'beauty'))=2
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12
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+
```
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13
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+
性能重視で考えると以下の記述も
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14
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+
```SQL
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15
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+
select user from x
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16
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group by user
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17
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+
having count(case when attr in ('pretty', 'beauty') then 1 end)=2
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12
18
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```
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2
追記
answer
CHANGED
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@@ -3,4 +3,10 @@
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3
3
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where exists(select 1 from X where user=t.user and attr ='pretty')
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4
4
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and exists(select 1 from X where user=t.user and attr ='beauty')
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5
5
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```
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6
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-
ですね。
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6
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+
ですね。
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7
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+
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8
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+
(user,attr)で一意なら以下の様な記述でも同様な結果になります。
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9
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+
```SQL
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10
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+
select distinct user from X t
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11
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+
where (select count(*) from X where user=t.user and attr in ('pretty', 'beauty'))=2
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12
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+
```
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1
訂正
answer
CHANGED
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@@ -1,6 +1,6 @@
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1
1
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```SQL
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2
2
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select distinct user from X t
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3
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-
where exists(select 1
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3
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+
where exists(select 1 from X where user=t.user and attr ='pretty')
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4
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-
and exists(select 1
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4
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+
and exists(select 1 from X where user=t.user and attr ='beauty')
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5
5
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```
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6
6
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ですね。
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