回答編集履歴
2
コード追記
test
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@@ -19,3 +19,93 @@
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`n`は`m`のタイプミスだと思いますが、`m`が定数でないと`std::vector<unshort[m]>`は作れません。
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---
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`m`が定数なら
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```C++
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#include<vector>
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#include<iostream>
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#define ushort unsigned short
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int main() {
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int n = 3;
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int x = 2;
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const int m = 4;
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ushort** a;
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a = new ushort * [n];//nはint
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for (int i = 0; i < x; i++) {
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a[i] = new ushort[m];
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// ダミーデータ格納
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for (int j = 0; j < m; j++)
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{
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a[i][j] = i * m + j;
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}
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}
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// コピー
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std::vector<ushort[m]> b(x);
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for (int i = 0; i < x; i++) {
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std::copy(a[i], a[i] + m, b[i]);
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}
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// 確認
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for (int i = 0; i < x; i++) {
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std::cout << "b[" << i << "]:";
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for (int j = 0; j < m; j++)
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{
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std::cout << b[i][j] << " ";
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}
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std::cout << std::endl;
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}
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return 0;
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}
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```
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要素がunshort[n]なvectorについて追記
test
CHANGED
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@@ -5,3 +5,17 @@
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std::vector<std::vector<ushort>> a(n, std::vector<ushort>(m));
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```
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---
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> ushort** を一つの要素がunshort[n]なvectorに変換
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nはint
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`n`は`m`のタイプミスだと思いますが、`m`が定数でないと`std::vector<unshort[m]>`は作れません。
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