回答編集履歴
2
追記
answer
CHANGED
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@@ -3,4 +3,11 @@
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3
3
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where ID3 in (
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4
4
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select ID3 from M_T group by ID3 having count(*) > 1
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5
5
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)
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6
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+
```
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7
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+
件数=要素数 ではなく、要素数での判断なら、
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8
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+
```SQL
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9
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+
delete from M_T
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10
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+
where ID3 in (
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11
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+
select ID3 from M_T group by ID3 having count(DISTINCT ID2) > 1
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12
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+
)
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6
13
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```
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1
推敲
answer
CHANGED
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@@ -1,5 +1,5 @@
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1
1
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```SQL
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2
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-
delete from M_T
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2
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+
delete from M_T
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3
3
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where ID3 in (
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4
4
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select ID3 from M_T group by ID3 having count(*) > 1
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5
5
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)
|