回答編集履歴
4
追記
answer
CHANGED
|
@@ -8,4 +8,16 @@
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|
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8
8
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where menber_id=mi.menber_id and start_date > mi.start_date
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9
9
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)
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10
10
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and end_date is not null
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|
11
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+
```
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12
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+
どっちが低コストか分かりませんが、別パターン
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13
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+
```SQL
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|
14
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+
SELECT m.id, m.name, mi.start_date, mi.end_date
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15
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+
from member_item mi inner join member m
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16
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+
om mi.menber_id = m.id
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17
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+
where (mi.menber_id, mi.start_date) in (
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18
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+
select menber_id, max(start_Date)
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|
19
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+
from member_item
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|
20
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+
group by menber_id
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21
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+
)
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22
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+
and end_date is not null
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11
23
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```
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3
推敲
answer
CHANGED
|
@@ -4,7 +4,8 @@
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|
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4
4
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from member_item mi inner join member m
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5
5
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om mi.menber_id = m.id
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6
6
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where not exists(
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7
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+
select 1 from member_item
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7
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-
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|
8
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+
where menber_id=mi.menber_id and start_date > mi.start_date
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8
9
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)
|
|
9
10
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and end_date is not null
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10
11
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```
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2
推敲
answer
CHANGED
|
@@ -1,6 +1,6 @@
|
|
|
1
1
|
最新を取得すれば、end_dateの判断だけですね。
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2
2
|
```SQL
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|
3
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-
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3
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+
SELECT m.id, m.name, mi.start_date, mi.end_date
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4
4
|
from member_item mi inner join member m
|
|
5
5
|
om mi.menber_id = m.id
|
|
6
6
|
where not exists(
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1
追記
answer
CHANGED
|
@@ -1,7 +1,8 @@
|
|
|
1
1
|
最新を取得すれば、end_dateの判断だけですね。
|
|
2
2
|
```SQL
|
|
3
3
|
select *
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|
4
|
+
from member_item mi inner join member m
|
|
4
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-
|
|
5
|
+
om mi.menber_id = m.id
|
|
5
6
|
where not exists(
|
|
6
7
|
select 1 from member_item where menber_id=mi.menber_id and start_date > mi.start_date
|
|
7
8
|
)
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