回答編集履歴
3
テキスト修正
answer
CHANGED
@@ -20,4 +20,19 @@
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20
20
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21
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const data2 = keys.map(key => map1.get(key));
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```
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23
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-
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012](https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012)
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23
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+
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012](https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012)
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### 追記
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27
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コメントにも返信しましたが、ご質問の要件が
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29
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30
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- 配列`data1`の要素である長さ2の配列の先頭要素の値(key)の昇順に、2番目の要素のアルファベットを取り出した配列を `data2` として得たい
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ということなのでしたら、以下のように sort を使えば得られます。
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```javascript
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const data2 = [...data1].sort(([k1],[k2]) => k1 - k2).map(([k,v]) => v);
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```
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- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/eYJNVBx?editors=0012](https://codepen.io/jun68ykt/pen/eYJNVBx?editors=0012)
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2
テキスト修正
answer
CHANGED
@@ -6,4 +6,18 @@
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6
6
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7
7
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const data2 = keys.map(key => data1.find(e => e[0] === key)[1]);
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8
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```
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9
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-
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012](https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012)
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9
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- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012](https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012)
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### 追記
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12
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または、 `data1` の内容を含むMapを作っておくという手もあります。
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```javascript
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const data1 = [ [8,"a"], [5,"b"], [12,"c"] ];
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const map1 = new Map(data1);
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const keys = [ 5, 8, 12 ];
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const data2 = keys.map(key => map1.get(key));
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```
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- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012](https://codepen.io/jun68ykt/pen/gOPpoqM?editors=0012)
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1
テキスト修正
answer
CHANGED
@@ -4,6 +4,6 @@
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4
4
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const data1 = [ [8,"a"], [5,"b"], [12,"c"] ];
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5
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const keys = [ 5, 8, 12 ];
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6
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-
const data2 = keys.map(key => data1.find(e => e[0] === key));
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const data2 = keys.map(key => data1.find(e => e[0] === key)[1]);
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8
8
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```
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9
9
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- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012](https://codepen.io/jun68ykt/pen/NWxqXej?editors=0012)
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