回答編集履歴
3
再帰処理を封印
answer
CHANGED
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@@ -11,4 +11,8 @@
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11
11
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さらに
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12
12
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```js
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13
13
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const A =(a,...b)=>'文字'+a+(b.length>1?A(...b):b);
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14
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+
```
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15
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+
再帰が評価されないようなので
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16
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+
```js
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17
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+
console.log(test.reduceRight((x,y)=>'文字'+y+x));
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14
18
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```
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2
短くも
answer
CHANGED
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@@ -7,4 +7,8 @@
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7
7
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じゃもう少し短く
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8
8
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```js
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9
9
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const A =(a,...b)=>'文字'+(b.length>1?a+A(...b):a+b);
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10
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+
```
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11
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+
さらに
|
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12
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+
```js
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13
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+
const A =(a,...b)=>'文字'+a+(b.length>1?A(...b):b);
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10
14
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```
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1
短く
answer
CHANGED
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@@ -3,4 +3,8 @@
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3
3
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var test = ['あ','い','う','え','お'];
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4
4
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const A =(a,b,...c)=> '文字'+(c.length?a+ A(b,...c):a+b);
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5
5
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console.log(A (...test));
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6
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+
```
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|
7
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+
じゃもう少し短く
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8
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+
```js
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9
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+
const A =(a,...b)=>'文字'+(b.length>1?a+A(...b):a+b);
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6
10
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```
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