回答編集履歴
1
chousei
answer
CHANGED
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@@ -5,4 +5,17 @@
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5
5
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sex='男' and ken_id=t1.id
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6
6
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) as cnt
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7
7
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from ken as t1
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8
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+
```
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9
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+
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10
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+
もしくは
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11
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```SQL
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12
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select t1.id as ken_id,
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13
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t1.name as ken_name,
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14
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coalesce(t2.cnt,0) as cnt
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15
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from ken as t1
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16
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left join (select ken_id,count(*) as cnt from member where
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17
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sex='男'
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18
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group by ken_id
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19
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) as t2
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20
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on t1.id=t2.ken_id
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8
21
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```
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