回答編集履歴
1
テキスト修正
answer
CHANGED
@@ -6,4 +6,11 @@
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6
6
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var result = _.zip(a, b, c).map(values =>
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7
7
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_.zipObject(["name", "age", "area"], values))
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8
8
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```
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9
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-
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/pojXXOZ?editors=0012](https://codepen.io/jun68ykt/pen/pojXXOZ?editors=0012)
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9
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+
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/pojXXOZ?editors=0012](https://codepen.io/jun68ykt/pen/pojXXOZ?editors=0012)
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10
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+
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11
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+
### 追記
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12
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+
以下のようにすれば、_.zipObject は使わなくても済みました。
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13
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+
```javascript
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14
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+
var result = _.zip(a, b, c).map(([name, age, area]) => ({ name, age, area }))
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15
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+
```
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16
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+
- **動作確認用CodePen:** [https://codepen.io/jun68ykt/pen/BaogXyY?editors=0012](https://codepen.io/jun68ykt/pen/BaogXyY?editors=0012)
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