回答編集履歴
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回答に追記
test
CHANGED
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@@ -1,3 +1,113 @@
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delayを使うと止まるので使ってはダメです
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待つ時間分の時刻を算出して、その時刻に到達したかどうかを判定するようにし、到達してない場合はそのままリターンするなり終了するなりしましょう
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---
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```Arduino
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unsigned long timo_set(int ms)
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{
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return mills()+ms;
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}
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bool timo_chk(unsigned long tim)
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{
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long a=tim - mills();
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return a<0;
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}
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unsigned long timer;
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int flag;
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void loop() {
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if(flag){
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if(timo_chk(timer)){
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digitalWrite(1, LOW);
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digitalWrite(2, LOW);
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digitalWrite(3, LOW);
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}
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flag=false;
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}
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int var = Serial.read();
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if(var<0) return;
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switch (var) {
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case '1':
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Serial.write(1);
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digitalWrite(1, HIGH);
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timer=timo_set(1000);
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flag=true;
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break;
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case '2':
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Serial.write(2);
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digitalWrite(2, HIGH);
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timer=timo_set(10);
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flag=true;
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break;
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case '3':
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Serial.write(3);
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digitalWrite(3, HIGH);
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timer=timo_set(10);
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flag=true;
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break;
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}
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110
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111
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```
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113
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＃素で書いてるので動作の保証はしない
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