回答編集履歴
2
修正
test
CHANGED
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@@ -16,10 +16,46 @@
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16
16
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17
17
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<input type="time" name="time" value="<?php echo ($time) ?? "" ?>">
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18
18
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19
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-
<input type="time" name="time" value="<?php echo ($time2) ?? "" ?>">
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19
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+
<input type="time" name="time2" value="<?php echo ($time2) ?? "" ?>">
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20
20
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21
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```
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22
22
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23
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25
25
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[Null 合体演算子](https://www.php.net/manual/ja/language.operators.comparison.php#language.operators.comparison.coalesce)
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26
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+
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27
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28
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29
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`1023`ならこんな感じで、「時間の型が正しいか」関数を作ってチェック。
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30
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31
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```php
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32
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33
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<?php
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34
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35
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function timeFormat($t):string
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36
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37
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{
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38
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39
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if(date("Hi",strtotime($t)) === $t){
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40
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41
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return date("H:i",strtotime($t));
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42
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43
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}
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45
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return "";
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46
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47
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}
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48
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49
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50
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51
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$time = "1023";
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52
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53
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$time2 = "";
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54
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55
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?>
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56
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57
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<input type="time" name="time" value="<?php echo timeFormat($time) ?>">
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58
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59
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<input type="time" name="time2" value="<?php echo timeFormat($time2) ?>">
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60
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61
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```
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1
修正
test
CHANGED
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@@ -1,18 +1,22 @@
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1
1
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DBから取得した情報を$timeにおさめてるならisset($time)は常にtrueになりませんか。(空とnullは別物です)
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2
2
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3
3
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4
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+
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5
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DBのデータの形式次第ですが、そもそも`10:23`のように入っているなら下記だけで良いと思います。
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4
6
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5
7
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```php
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6
8
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7
9
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<?php
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8
10
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9
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-
$time =
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11
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$time = "10:23";
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10
12
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11
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-
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13
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$time2 = "";
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15
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?>
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14
16
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15
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<input type="time" name="time" value="<?php echo ($time) ?? "" ?>">
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18
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+
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19
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<input type="time" name="time" value="<?php echo ($time2) ?? "" ?>">
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16
20
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21
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```
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18
22
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