回答編集履歴
3
別解
answer
CHANGED
|
@@ -4,4 +4,11 @@
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|
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4
4
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puts ("*" * n).gsub(/*{5}/,"*****\n")
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5
5
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```
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6
6
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別解
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|
7
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-
`puts "*****\n" * (n/5) + "*" * (n%5)`
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7
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+
`puts "*****\n" * (n/5) + "*" * (n%5)`
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8
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+
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9
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+
更に別解
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10
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+
上のだと nが 3京とかだとメモリーががりなくなるので
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11
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+
```
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12
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+
(n/5).times { puts "*****"}
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13
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+
puts "*" * (n%5)
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14
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+
```
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2
追記
answer
CHANGED
|
@@ -3,5 +3,5 @@
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3
3
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n = gets.to_i
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4
4
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puts ("*" * n).gsub(/*{5}/,"*****\n")
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5
5
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```
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6
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-
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6
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+
別解
|
|
7
7
|
`puts "*****\n" * (n/5) + "*" * (n%5)`
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1
別解
answer
CHANGED
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@@ -2,4 +2,6 @@
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2
2
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print "何個*を表示しますか？"
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3
3
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n = gets.to_i
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4
4
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puts ("*" * n).gsub(/*{5}/,"*****\n")
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5
|
-
```
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5
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+
```
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6
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+
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7
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+
`puts "*****\n" * (n/5) + "*" * (n%5)`
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