回答編集履歴
3
元コードに対する対応を追記
answer
CHANGED
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@@ -10,4 +10,24 @@
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10
10
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loc = (41, 141)
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11
11
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nearest = min(pref_capitals, key=lambda geo: (loc[0] - geo[0])**2 + (loc[1] - geo[1])**2)
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12
12
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print(nearest, pref_capitals[nearest])
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13
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+
```
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14
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+
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15
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+
元のやり方なら、keysのイテレータを作って、nextで最初の要素を取り出して仮の最小値にして、残りのkyesでループするのが楽です。
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16
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+
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17
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+
```
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18
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+
pref_capitals = {(43.06417, 141.34694): "北海道（札幌）",
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19
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+
(40.82444, 140.74): "青森県（青森市）",
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20
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+
(39.70361, 141.1525): "岩手県（盛岡市）"
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21
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+
}
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22
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+
loc = (41, 141)
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23
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+
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24
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+
keys = iter(pref_capitals.keys())
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25
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+
key = next(keys)
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26
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+
min_calc = (key[0] - loc[0])**2 + (key[1] - loc[1])**2
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27
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+
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28
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+
for key in keys:
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29
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+
calc = (key[0] - loc[0])**2 + (key[1] - loc[1])**2
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30
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+
if min_calc > calc:
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31
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+
min_calc = calc
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|
32
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+
print(min_calc)
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13
33
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```
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2
説明追加
answer
CHANGED
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@@ -1,3 +1,5 @@
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1
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+
一番近い、距離が一番小さい、min関数の出番。
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2
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+
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1
3
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```
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2
4
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pref_capitals = {(43.06417, 141.34694): "北海道（札幌）",
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3
5
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(40.82444, 140.74): "青森県（青森市）",
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1
コード変更
answer
CHANGED
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@@ -6,10 +6,6 @@
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6
6
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7
7
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8
8
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loc = (41, 141)
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9
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-
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|
10
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-
def distance(geo):
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11
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-
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9
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+
nearest = min(pref_capitals, key=lambda geo: (loc[0] - geo[0])**2 + (loc[1] - geo[1])**2)
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12
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-
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13
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-
nearest = min(pref_capitals, key=distance)
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14
10
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print(nearest, pref_capitals[nearest])
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15
11
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```
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