回答編集履歴
3
ちょうせい
answer
CHANGED
@@ -27,8 +27,18 @@
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27
27
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/* fetchで送信 */
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28
28
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const body=new FormData();
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29
29
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body.append("myfile", blob,"test.png");
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30
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+
const url="up.php";
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30
31
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const method = "POST";
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31
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-
fetch(
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32
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+
fetch(url, {method, body}).then(data=>data.text()).then(console.log)
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33
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+
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34
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+
/* 念の為、ajaxなら上記fetchの行をこうしてください
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35
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const xhr = new XMLHttpRequest();
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36
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xhr.open(method,url);
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37
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new Promise(resolve=>{
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38
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xhr.addEventListener("load" ,e=>resolve(e.target.response));
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39
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}).then(console.log);
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40
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xhr.send(body);
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41
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+
*/
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42
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});
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33
43
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34
44
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</script>
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2
chousei
answer
CHANGED
@@ -2,7 +2,7 @@
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2
2
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3
3
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```javascript
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4
4
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<script>
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5
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-
window.addEventListener('DOMContentLoaded',
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5
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+
window.addEventListener('DOMContentLoaded', ()=>{
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6
6
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/* canvas作成 */
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7
7
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const canvas = document.createElement( "canvas" ) ;
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8
8
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canvas.width=200;
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1
chousei
answer
CHANGED
@@ -22,7 +22,7 @@
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22
22
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const bin = atob(dataurl.split(',')[1]);
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23
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const buffer = new Uint8Array(bin.length);
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24
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[].forEach.call(bin,(x,y)=>buffer[y]=bin.charCodeAt(y));
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25
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-
const blob = new Blob([buffer.buffer], {type
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25
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+
const blob = new Blob([buffer.buffer], {type});
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26
26
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27
27
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/* fetchで送信 */
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28
28
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const body=new FormData();
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