回答編集履歴
3
chousei
answer
CHANGED
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@@ -129,4 +129,38 @@
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129
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|2019-07-01|1|2|
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|2019-08-01|1|2|
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|2019-09-01|1|1|
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-
|2019-10-01|1|1|
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|2019-10-01|1|1|
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# カレンダーを利用
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```SQL
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create table user_info_table(id int primary key,UserInsertDate date,UpdateDate date,RegistrationCode int);
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insert into user_info_table values
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(1,'20190401','20191001',1),
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(2,'20190301','20190801',1),
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(3,'20190401','20190601',2);
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/*とりあえず1年分投入してますが、使い回すので100年分くらい投入しておくとよい*/
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create table nengetu(d date unique);
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insert into nengetu values
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('20190101'),
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('20190201'),
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('20190301'),
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('20190401'),
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('20190501'),
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('20190601'),
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('20190701'),
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('20190801'),
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('20190901'),
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('20191001'),
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('20191101'),
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('20191201');
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```
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- 集計
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```SQL
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select d,RegistrationCode,count(*) as cnt from user_info_table as t1
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inner join nengetu as t2
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on t2.d between t1.UserInsertDate and t1.UpdateDate
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group by d,RegistrationCode
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order by d,RegistrationCode;
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```
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2
procedure
answer
CHANGED
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@@ -24,4 +24,109 @@
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|10月|1|1|
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という結果を発生させるのですか？
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27
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-
カウントが1の理由がわかりません
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カウントが1の理由がわかりません
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# procedure
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この手の処理はprocedureを使ってテンポラリーテーブルを作って処理します
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- 元データ
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```SQL
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34
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create table user_info_table(id int primary key,UserInsertDate date,UpdateDate date,RegistrationCode int);
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insert into user_info_table values
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(1,'20190401','20191001',1),
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(2,'20190301','20190801',1),
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38
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(3,'20190401','20190601',2);
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```
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40
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- procedure作成
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1回だけ以下を実行
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```SQL
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create table user_info_table(id int primary key,UserInsertDate date,UpdateDate date,RegistrationCode int);
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insert into user_info_table values
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(1,'20190401','20191001',1),
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(2,'20190301','20190801',1),
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(3,'20190401','20190601',2);
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;
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drop procedure if exists proc_test;
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delimiter //
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create procedure proc_test()
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begin
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declare a int;
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declare b date;
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declare c date;
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declare d int;
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declare done int default 0;
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declare cur cursor for
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select id,UserInsertDate,UpdateDate,RegistrationCode from user_info_table;
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declare continue handler for sqlstate '02000' set done = 1;
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set @sql="";
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open cur;
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repeat
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fetch cur into a,b,c,d;
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if not done then
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set @date=b;
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while @date<=c do
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if @sql="" then
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create temporary table tmp(nengetu date,RegistrationCode int);
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set @sql="insert into tmp ";
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else
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set @sql=concat(@sql,"union all ");
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end if;
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set @sql=concat(@sql,"select '",@date,"',",d," ");
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set @date=@date + interval 1 month;
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end while;
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end if;
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until done end repeat;
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close cur;
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PREPARE stmt from @sql;
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EXECUTE stmt;
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end
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//
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delimiter ;
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```
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- テスト
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```SQL
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call proc_test;
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select * from tmp;
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```
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|nengetu|RegistrationCode|
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|:--|--:|
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95
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|2019-04-01|1|
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96
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|2019-05-01|1|
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97
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|2019-06-01|1|
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98
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|2019-07-01|1|
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99
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|2019-08-01|1|
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100
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|2019-09-01|1|
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101
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|2019-10-01|1|
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102
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|2019-03-01|1|
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103
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|2019-04-01|1|
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104
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|2019-05-01|1|
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105
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|2019-06-01|1|
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|2019-07-01|1|
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107
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|2019-08-01|1|
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108
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|2019-04-01|2|
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109
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|2019-05-01|2|
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110
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|2019-06-01|2|
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111
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112
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113
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- 集計
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114
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```SQL
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115
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call proc_test;
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116
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select nengetu,RegistrationCode,count(*) as cnt from tmp
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117
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group by nengetu,RegistrationCode;
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118
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119
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```
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120
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|nengetu|RegistrationCode|cnt|
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121
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|:--|--:|--:|
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122
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|2019-03-01|1|1|
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123
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|2019-04-01|1|2|
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124
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|2019-04-01|2|1|
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125
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|2019-05-01|1|2|
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126
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|2019-05-01|2|1|
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127
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|2019-06-01|1|2|
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128
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|2019-06-01|2|1|
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129
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|2019-07-01|1|2|
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130
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|2019-08-01|1|2|
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131
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|2019-09-01|1|1|
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132
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|2019-10-01|1|1|
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1
tuiki
answer
CHANGED
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@@ -2,4 +2,26 @@
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2
2
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ダミーで100年分くらいデータを作っておき、joinすればよいでしょう
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3
3
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4
4
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具体的には命題の情報では回答が難しいので
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5
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サンプルをcreate table+insert形式で例示ください
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5
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サンプルをcreate table+insert形式で例示ください
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6
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7
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# 追記
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8
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9
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```SQL
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10
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create table user_info_table(id int primary key,UserInsertDate date,UpdateDate date,RegistrationCode int);
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11
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insert into user_info_table values
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12
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(1,'20190401','20191001',1);
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13
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```
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14
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というレコードが１つしかないテーブルから
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15
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16
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|年月|RegistrationCode|カウント|
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17
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|--:|--:|--:|
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|4月|1|1|
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19
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|5月|1|1|
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20
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|6月|1|1|
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21
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|7月|1|1|
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22
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|8月|1|1|
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23
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|9月|1|1|
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24
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|10月|1|1|
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25
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+
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26
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+
という結果を発生させるのですか？
|
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27
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+
カウントが1の理由がわかりません
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