回答編集履歴
1
調整
answer
CHANGED
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@@ -16,4 +16,32 @@
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16
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) as t1,JSON_TABLE(val, '$[*]' COLUMNS (value INT PATH '$')) AS j
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) as t2
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group by collection_time
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19
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+
```
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+
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# 調整版
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22
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各データごとに平均を出して、そのデータを平均する
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```sql
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select collection_time,
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min(min) as min,
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max(max) as max,
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avg(avg) as avg
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from(
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select collection_time,mac,
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min(value) as min,
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max(value) as max,
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avg(value) as avg
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from (
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select collection_time,mac,value
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from
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(
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select
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collection_time,mac,
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replace(group_concat(JSON_EXTRACT(mv,'$.*')),'],[',',') as val
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from logs
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group by collection_time,mac
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) as t1,JSON_TABLE(val, '$[*]' COLUMNS (value INT PATH '$')) AS j
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) as t2
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group by collection_time,mac
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) as t3
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group by collection_time
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47
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```
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