回答編集履歴
4
追記
test
CHANGED
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@@ -21,3 +21,5 @@
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21
21
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and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 2 days)
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22
22
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23
23
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```
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24
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+
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25
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+
※特定期間の最新データとしたい場合は、期間の条件を追加
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3
訂正
test
CHANGED
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@@ -2,7 +2,7 @@
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2
2
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3
3
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```SQL
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4
4
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5
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-
select
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5
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+
select *
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6
6
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7
7
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from table1 as t1
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8
8
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@@ -20,6 +20,4 @@
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20
20
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21
21
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and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 2 days)
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22
22
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23
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-
GROUP BY SC
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24
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-
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25
23
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```
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2
推敲
test
CHANGED
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@@ -12,11 +12,11 @@
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12
12
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13
13
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and not exists(select 1 from table1 where SC=t1.SC and t1.date<date)
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14
14
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15
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-
-- １日前のtodays_close > ago_closeが存在
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15
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+
-- １日前のtodays_close > ago_closeが存在
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16
16
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17
17
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and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 1 days)
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18
18
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19
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-
-- ２日前のtodays_close > ago_closeが存在
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19
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+
-- ２日前のtodays_close > ago_closeが存在
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20
20
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21
21
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and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 2 days)
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22
22
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1
訂正
test
CHANGED
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@@ -14,11 +14,11 @@
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14
14
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15
15
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-- １日前のtodays_close > ago_closeが存在するか
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16
16
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17
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-
and exists(select 1 from table1 where todays_close > ago_close and date=t1.date - interval 1 days)
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17
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+
and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 1 days)
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18
18
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19
19
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-- ２日前のtodays_close > ago_closeが存在するか
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20
20
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21
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-
and exists(select 1 from table1 where todays_close > ago_close and date=t1.date - interval 2 days)
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21
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+
and exists(select 1 from table1 where todays_close > ago_close and SC=t1.SC and date=t1.date - interval 2 days)
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22
22
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23
23
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GROUP BY SC
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24
24
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