回答編集履歴
2
見直し
test
CHANGED
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@@ -36,18 +36,48 @@
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```
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countやtimeといった、SQLの予約語をそのままカラム名に使うのは混乱の元なので、
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-
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間に合うならカラム名を変えてテーブルを作り直したほうが良いです。
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それが出来かねるのであれば、例えば
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```php
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$reserve_query = "SELECT COUNT(*) AS CNT FROM reserve WHERE reserve_shop_id=:shop_id";
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```
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$reserve_query = <<<EOT
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SELECT
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`reserve_id`, `reserve_shop_id`, `count`, `time`,
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`reserve_comment`, `reserve_time`, `reserve_tel`, `reserve_push_id`
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FROM reserve
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WHERE reserve_shop_id = :shop_id
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EOT;
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```
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を試したり
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```
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$reserve_query = <<<EOT
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SELECT
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`reserve_id`, `reserve_shop_id`, `count` AS "CNT", `time` AS "TM",
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`reserve_comment`, `reserve_time`, `reserve_tel`, `reserve_push_id`
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FROM reserve
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WHERE reserve_shop_id = :shop_id
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EOT;
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```
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とか試すといいかも。
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1
見直し
test
CHANGED
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@@ -1,13 +1,53 @@
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1
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-
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```php
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// reserveテーブルのreserve_shop_idからshop名を取り出す
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$reserve_query = "SELECT * FROM reserve WHERE reserve_shop_id=:shop_id";
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$reserve_stmt = $pdo->prepare($reserve_query);
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$reserve_stmt->bindValue(':shop_id', $shop_id, PDO::PARAM_INT);
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$reserve_stmt->execute();
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$reserve_stmt->debugDumpParams();
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//結果->SQL: [52] SELECT * FROM reserve WHERE reserve_shop_id=:shop_id Params: 1 Key: Name: [8] :shop_id paramno=0 name=[8] ":shop_id" is_param=1 param_type=1
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//var_dump($shop_id); ->int(4)
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// reserveテーブルから予約情報の取り出し
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$arr_reserve = [];
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while ($row = $reserve_stmt->fetchAll(PDO::FETCH_ASSOC)) {
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$arr_reserve[] = [
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'count' => $row['count'], <-エラー箇所
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];
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}
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//var_dump($arr_reserve);->array(1) { [0]=> array(6) { ["count"]=> NULL ["time"]=> NULL} }
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```
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39
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テーブル reserve に、カラム count っていうのが存在するかどうかわからないけど、あるんだよね？
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9
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-
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もしもカラム count っていうのがないのに使っているのなら、そりゃエラーになりますよね。
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もしかして、
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```php
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$reserve_query = "SELECT COUNT(*) AS CNT FROM reserve WHERE reserve_shop_id=:shop_id";
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```
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とかすれば、`$row['CNT']`としてレコード数が取得できたりしますけど。
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