回答編集履歴
1
指摘を受けて.stop()追加
answer
CHANGED
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@@ -6,11 +6,12 @@
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6
6
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timeoutId = setTimeout(function () {
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7
7
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var s = $(window).scrollTop();
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8
8
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if (s_old < s && m <= s) {
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9
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-
$("#ST-top").delay(1500).fadeIn(1000);
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9
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+
$("#ST-top").stop(true, true).delay(1500).fadeIn(1000);
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10
10
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} else {
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11
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-
$("#ST-top").hide();
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11
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+
$("#ST-top").stop(true, true).hide();
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12
12
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}
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13
13
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14
14
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s_old = s;
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15
15
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}, 500);
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16
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-
```
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16
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+
```
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17
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+
[https://api.jquery.com/stop/](https://api.jquery.com/stop/)
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