回答編集履歴
4
SQL修正
test
CHANGED
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@@ -40,11 +40,11 @@
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40
40
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41
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SELECT user_id
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FROM Table1
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+
FROM Table1 AS a
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WHERE item_id=1 AND
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47
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-
not exists (select user_id from table1 b where a.user_id = b.user_id AND item_id = 2);
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not exists (select user_id from table1 AS b where a.user_id = b.user_id AND item_id = 2);
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48
48
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49
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```
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50
50
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3
さらに回答追加
test
CHANGED
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@@ -31,3 +31,21 @@
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31
31
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```
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32
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+
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not exists を使うなら、
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+
```SQL
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40
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+
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41
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+
SELECT user_id
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+
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FROM Table1
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WHERE item_id=1 AND
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46
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+
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not exists (select user_id from table1 b where a.user_id = b.user_id AND item_id = 2);
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48
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+
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49
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```
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50
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+
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2
回答追加
test
CHANGED
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@@ -13,3 +13,21 @@
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13
13
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WHERE a.item_id=1 AND b.user_id Is Null;
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14
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```
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+
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18
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19
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+
IN演算子を使ってもよさそう。
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```SQL
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+
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SELECT user_id
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FROM Table1
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WHERE item_id=1 AND user_id Not In (select user_id from table1 where item_id = 2);
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+
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31
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```
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32
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+
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33
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+
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1
SQLコード修正
test
CHANGED
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@@ -4,7 +4,7 @@
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4
4
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5
5
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```SQL
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6
6
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7
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-
SELECT a.user_id
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7
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+
SELECT a.user_id
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8
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FROM Table1 AS a LEFT JOIN (select user_id From Table1 where item_id = 2) AS b
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10
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