回答編集履歴
2
結合分を少し修正
answer
CHANGED
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@@ -14,14 +14,12 @@
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14
14
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c.column_7 as DATA03
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15
15
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d.column_2 as DATA04
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16
16
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from
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17
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-
a LEFT OUTER JOIN c on a.column_3 = c.column_3
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17
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+
a LEFT OUTER JOIN c on a.column_3 = c.column_3 and a.column_4 = c.column_4
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18
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-
LEFT OUTER JOIN c on a.column_3 = c.column_3
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19
18
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LEFT OUTER JOIN c on b.column_3 = c.column_3
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20
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-
....
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19
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+
LEFT OUTER JOIN d on c.column_3 = d.column_3 and c.column_4 = d.column_4
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21
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-
......
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22
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-
......
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23
20
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where
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24
21
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c.column_6 < 21
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25
22
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```
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26
23
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27
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-
こいつで、一旦は進めていこうと思います。ありがとうございました。
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24
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+
こいつで、一旦は進めていこうと思います。ありがとうございました。
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25
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+
（結合の2行目の「`LEFT OUTER JOIN c on b.column_3 = c.column_3`」は、ひょっとしたら「`LEFT OUTER JOIN b on c.column_3 = b.column_3`」とすべきなのかもしれませんが）
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1
カンマが足らなかったので追加
answer
CHANGED
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@@ -5,8 +5,8 @@
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5
5
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```sql
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6
6
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WITH
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7
7
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a as (select * from AA)
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8
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-
b as (select * from BB)
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8
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+
, b as (select * from BB)
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9
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-
c as (select .... from CC)
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9
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+
, c as (select .... from CC)
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10
10
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, d as (select .... from DD)
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11
11
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select
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12
12
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a.column_1 as DATA01
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