回答編集履歴
2
修正
test
CHANGED
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@@ -81,3 +81,27 @@
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81
81
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- uid=2は2件しかないので3件表示されない
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82
82
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83
83
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- uid=3の3位が2件あるので4件表示されている
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84
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+
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85
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+
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86
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+
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87
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+
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88
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+
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89
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+
# 同順位を認めない
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90
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+
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91
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- 2次ソートにidを指定
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92
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+
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93
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+
```SQL
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94
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+
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95
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select id,uid,pid,regist,
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96
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+
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97
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+
(select count(*)+1 from tbl
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98
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+
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99
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where uid=t1.uid and (regist>t1.regist or regist=t1.regist and id>t1.id )) rank
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100
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+
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101
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from tbl as t1
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102
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+
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103
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having rank<=3
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104
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+
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105
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order by uid,rank
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106
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+
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107
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```
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1
sample
test
CHANGED
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@@ -19,3 +19,65 @@
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19
19
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buyHistoryの具体的なサンプルデータと期待する結果を例示されると
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20
20
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21
21
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それに合わせた回答が付きやすいでしょう
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22
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+
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23
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+
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24
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+
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25
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+
# sample
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26
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+
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27
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+
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28
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+
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29
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一応サンプルだけ
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30
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+
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31
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+
```SQL
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32
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+
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33
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create table tbl(id int primary key auto_increment,uid int not null,pid int not null,regist datetime);
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34
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+
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35
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insert into tbl(uid,pid,regist) values
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36
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+
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37
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+
(1,101,'2018-01-01 00:10:00'),
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38
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+
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39
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+
(1,102,'2018-01-01 00:20:00'),
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40
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+
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41
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+
(2,101,'2018-01-01 00:10:00'),
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42
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+
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43
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+
(1,103,'2018-01-01 00:40:00'),
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44
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+
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45
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+
(1,101,'2018-01-01 00:50:00'),
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46
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+
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47
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+
(1,104,'2018-01-01 00:30:00'),
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48
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+
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49
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+
(2,102,'2018-01-01 00:20:00'),
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50
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+
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51
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+
(3,101,'2018-01-01 00:10:00'),
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52
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+
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53
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+
(3,103,'2018-01-01 00:20:00'),
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54
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+
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55
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+
(3,105,'2018-01-01 00:20:00'),
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56
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+
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57
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+
(3,107,'2018-01-01 00:30:00'),
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58
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+
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59
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+
(3,109,'2018-01-01 00:40:00');
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60
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+
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61
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+
```
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62
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+
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63
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+
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64
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+
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65
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- ユーザーごと最新3件を表示
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66
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+
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67
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+
```SQL
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68
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+
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69
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+
select id,uid,pid,regist,
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70
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+
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71
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+
(select count(*)+1 from tbl where uid=t1.uid and regist>t1.regist) rank
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72
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+
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73
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from tbl as t1
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74
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+
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75
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+
having rank<=3
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76
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+
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77
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+
order by uid,rank
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78
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+
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79
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+
```
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80
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+
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81
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+
- uid=2は2件しかないので3件表示されない
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82
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+
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83
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+
- uid=3の3位が2件あるので4件表示されている
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