回答編集履歴
2
条件の次n回スキップ
answer
CHANGED
|
@@ -27,4 +27,21 @@
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|
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27
27
|
|
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28
28
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else:
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29
29
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print(i)
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|
30
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+
```
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|
31
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+
# 次をスキップ
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32
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+
3の時次n回スキップ
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|
33
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+
```python
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34
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+
n = 0
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35
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+
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36
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+
for i in range(1, 11):
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|
37
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+
|
|
38
|
+
if n > 0:
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|
39
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+
n -= 1
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|
40
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+
continue
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41
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+
|
|
42
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+
elif i == 3:
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43
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+
# スキップ数
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|
44
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+
n = 1
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|
45
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+
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46
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+
print(i)
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30
47
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```
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1
スキップ追加
answer
CHANGED
|
@@ -6,4 +6,25 @@
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6
6
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continue
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7
7
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else:
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8
8
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print(i)
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9
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+
```
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10
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+
|
|
11
|
+
# スキップ
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|
12
|
+
4のとき次の1回スキップ
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|
13
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+
```python
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|
14
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+
# スキップ数
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|
15
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+
n = 0
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|
16
|
+
|
|
17
|
+
for i in range(1, 11):
|
|
18
|
+
|
|
19
|
+
if n > 0:
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|
20
|
+
n -= 1
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|
21
|
+
continue
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|
22
|
+
|
|
23
|
+
elif i == 4:
|
|
24
|
+
# スキップ数
|
|
25
|
+
n = 1
|
|
26
|
+
continue
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|
27
|
+
|
|
28
|
+
else:
|
|
29
|
+
print(i)
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|
9
30
|
```
|