回答編集履歴
2
調整
answer
CHANGED
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@@ -16,6 +16,9 @@
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16
16
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}
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17
17
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print $sql.";<br>";
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18
18
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print_r($data);
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19
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+
/*
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20
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+
$pdo = new PDO($dsn, $user,$password);
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21
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+
$stmt = $pdo->prepare($sql);
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19
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-
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22
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+
$stmt->execute($data);
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20
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-
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23
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+
*/
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21
24
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```
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1
typo
answer
CHANGED
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@@ -11,7 +11,7 @@
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11
11
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$data[]=$postedType;
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12
12
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}
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13
13
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if(is_array($postedWords)){
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14
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-
$sql.="and
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14
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+
$sql.="and word not in (".implode(",",array_fill(0,count($postedWords),"?")).") ";
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15
15
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$data=array_merge($data,$postedWords);
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16
16
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}
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17
17
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print $sql.";<br>";
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