回答編集履歴
2
調整
answer
CHANGED
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@@ -12,4 +12,30 @@
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12
12
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select sale_date,sum(discount_price) from tbl as t1
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where not exists(select 1 from tbl where t1.sale_date<sale_date)
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group by sale_date
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```
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# idごと
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```SQL
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create table tbl(id int,sale_date date,discount_price int);
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insert into tbl values
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(1,'2018-11-02',2390),
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(1,'2018-11-02',510),
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(1,'2017-10-22',5280),
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(2,'2016-04-04',4608),
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(2,'2018-10-12',2200);
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```
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- 集計1
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30
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```SQL
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select id,sale_date,sum(discount_price) from tbl
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group by id,sale_date
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having (id,sale_date) in (select id,max(sale_date) from tbl group by id)
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```
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- 集計2
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```SQL
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select id,sale_date,sum(discount_price) from tbl as t1
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where not exists(select 1 from tbl where t1.id=id and t1.sale_date<sale_date)
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group by id,sale_date
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15
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```
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1
tuiki
answer
CHANGED
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@@ -3,4 +3,13 @@
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3
3
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select sale_date,sum(discount_price) from tbl
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group by sale_date
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having sale_date=(select max(sale_date) from tbl)
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```
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# 追記
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絞ってから集計
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```SQL
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12
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select sale_date,sum(discount_price) from tbl as t1
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13
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where not exists(select 1 from tbl where t1.sale_date<sale_date)
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group by sale_date
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6
15
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```
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