回答編集履歴
2
調整
test
CHANGED
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@@ -33,3 +33,15 @@
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33
33
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34
34
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35
35
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```
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36
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+
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37
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+
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38
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+
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39
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- unionしない別解
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40
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+
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41
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+
```SQL
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42
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+
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43
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select id,status,(select case when status is null then 1 else count(*) end from tbl where status=t1.status) as cnt from tbl as t1
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44
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+
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45
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where not exists (select 1 from tbl where t1.id>id and t1.status=status)
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46
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+
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47
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```
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1
参考
test
CHANGED
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@@ -1 +1,35 @@
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1
1
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そもそもstatusでgroup byしてidを表示することはできませんよ
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2
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3
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4
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5
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# sample
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6
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7
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8
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9
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```SQL
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10
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+
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11
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create table tbl(id int,status int null);
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12
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13
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insert into tbl values(1,1000),(2,1000),(3,2000),(4,2000),(5,null),(6,null),(7,3000);
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14
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+
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15
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```
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16
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+
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17
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18
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19
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- 集計
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20
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21
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```SQL
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22
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23
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select * from(
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24
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25
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select min(id) as id,status,count(*) as cnt from tbl where status is not null group by status
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26
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27
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union all select id,status,1 from tbl where status is null
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28
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29
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) as t
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30
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31
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order by id
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32
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33
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34
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35
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```
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