回答編集履歴
2
追記
answer
CHANGED
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@@ -35,4 +35,28 @@
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35
35
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console.log("end");
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36
36
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});
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37
37
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});
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38
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+
```
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39
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+
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40
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+
# 一連の処理後に更に処理
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41
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+
```javascript
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42
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function f() {
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43
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var d=$.Deferred();
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44
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var deferredArray=[];
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45
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for(let i = 0; i < 10; i++) {
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46
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var deferredFunc = function(){
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47
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return $.ajax({url:"y.php"}).then(function(){
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48
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console.log(i);
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49
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});
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50
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};
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51
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deferredArray.push(deferredFunc());
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52
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}
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53
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$.when.apply(null, deferredArray).then(function(){
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54
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console.log("end");
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55
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d.resolve();
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56
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});
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57
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return d.promise();
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58
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}
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59
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f().then(function(){
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60
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console.log('test');
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61
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});
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38
62
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```
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1
調整
answer
CHANGED
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@@ -20,4 +20,19 @@
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20
20
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<?PHP
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21
21
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sleep($_GET["sleep"]);
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22
22
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?>
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23
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```
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24
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+
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25
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# Promiseが返らなくても
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26
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Defferedを複数発行すれば非同期全体をまってくれる（Promise.all）はずですけどね
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27
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```javascript
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28
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$(function(){
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29
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console.log("start");
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30
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var defs=Array(3).fill(null).map(function(){return $.Deferred()});
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31
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setTimeout(function(){console.log(1);return defs[0].resolve()},3000),
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32
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setTimeout(function(){console.log(2);return defs[1].resolve()},1000),
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33
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setTimeout(function(){console.log(3);return defs[2].resolve()},2000),
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34
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$.when.apply(null,defs).then(function(){
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35
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console.log("end");
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36
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+
});
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37
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});
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23
38
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```
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