回答編集履歴
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list
answer
CHANGED
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@@ -6,4 +6,16 @@
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6
6
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good_list = [row for row in f if 'good' in path]
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7
7
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f.seek(0) #追加
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8
8
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bad_list = [row for row in f if 'bad' in path]
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9
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+
```
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10
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+
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11
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【追記】
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12
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+
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13
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処理時間とかは分かりませんが、こっちの方が気持ち悪くないかも。
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14
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+
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15
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```python
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16
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# リスト内法表記
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17
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with open(path, encoding='utf-8') as f:
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18
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rows = list(f) #リスト化
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19
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good_list = [row for row in rows if 'good' in path]
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20
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bad_list = [row for row in rows if 'bad' in path]
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9
21
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```
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