回答編集履歴
2
コード修正
answer
CHANGED
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@@ -18,13 +18,13 @@
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18
18
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->whereDate('date', '<=', '2018-08-31')
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19
19
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->get()
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20
20
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->groupBy('date')
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21
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-
->map(function (
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21
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+
->map(function ($byDate) {
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22
22
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return $byDate
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23
23
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->groupBy('product_id')
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24
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-
->map(function (
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24
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+
->map(function ($byProductId) {
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25
25
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return $byProductId
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26
26
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->groupBy('type')
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27
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-
->map(function (
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27
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+
->map(function ($byType) {
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28
28
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return $byType->first()['count'];
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29
29
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})
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30
30
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->all();
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1
groupByとmapを使った例を追記
answer
CHANGED
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@@ -9,4 +9,27 @@
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9
9
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->each(function ($item) use (&$dictionary) {
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10
10
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$dictionary[$item['date']][$item['product_id']][$item['type']] = $item['count'];
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11
11
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});
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12
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+
```
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13
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+
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14
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+
最初に書いたやり方だとこんな感じ。
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15
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+
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16
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+
```php
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17
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+
$dictionary = App\HogeTable::whereDate('date', '>=', '2018-08-01')
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18
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->whereDate('date', '<=', '2018-08-31')
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19
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+
->get()
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20
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+
->groupBy('date')
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21
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+
->map(function (Collection $byDate) {
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22
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+
return $byDate
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23
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+
->groupBy('product_id')
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24
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+
->map(function (Collection $byProductId) {
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25
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return $byProductId
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26
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+
->groupBy('type')
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27
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+
->map(function (Collection $byType) {
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28
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return $byType->first()['count'];
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29
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})
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30
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->all();
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31
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+
})
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32
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+
->all();
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33
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+
})
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34
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+
->all();
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12
35
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```
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