回答編集履歴
1
調整
answer
CHANGED
@@ -8,7 +8,8 @@
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8
8
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var p=n1.parentNode;
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9
9
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var idx=[].map.call(p.children,function(x){return x;}).indexOf(n1);
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10
10
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var num=3;
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11
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-
var n2=[].filter.call(p.children,function(x,y){return y==idx+num;}).shift();
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11
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+
// var n2=[].filter.call(p.children,function(x,y){return y==idx+num;}).shift();
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12
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+
var n2=p.children[idx+num]; //think49さんの回答のパクリ
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12
13
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console.log(n2.id);
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13
14
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});
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14
15
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</script>
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