回答編集履歴
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調整
test
CHANGED
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@@ -1 +1,63 @@
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$.ajaxでdataを指定してないからでしょう
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# sample
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postが前提であればデータ渡しはformdataがよいでしょう
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```javascript
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10
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<script>
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$(function () {
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$('#form').on('submit',function(e){
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var fd = new FormData($('#form').get(0));
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e.preventDefault();
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$.ajax({
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"url": 'ajax.php',
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"type": "POST",
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"dataType": "html",
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"data":fd,
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"cache":false,
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"processData": false,
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"contentType": false,
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}).done(function(data){
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console.log(data);
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});
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});
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});
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</script>
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<form id="form" name="search" action="" method="POST">
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<input type="radio" id="color01" name="color" value="red" checked><label for="color01">赤</label>
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<input type="radio" id="color02" name="color" value="blue"><label for="color02">青</label>
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<button class="submit" value="検索">検索</button>
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</form>
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61
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```
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63
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一応サブミットしたときにバックグラウンドで処理してあります
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