回答編集履歴
1
sample
test
CHANGED
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@@ -7,3 +7,81 @@
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またestateが複数stattion情報をもつなら正規化する必要があります
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# sample
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14
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15
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冗長に処理すればこんな感じ
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- 元データ
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19
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```SQL
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create table route(ro_id varchar(100) primary key,ro_name varchar(30));
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insert into route values("kdfnakdnfakndfajfajdb","山手線");
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create table station(st_id varchar(100) primary key,ro_id varchar(100),st_name varchar(30));
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insert into station values("nfwiha4hqwkefnjg","kdfnakdnfakndfajfajdb","渋谷駅");
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create table region(re_id varchar(100) primary key,re_name varchar(30));
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insert into region values("faknfakndfa","港区");
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create table estate(es_id varchar(100) primary key,es_name varchar(30),re_id varchar(100));
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insert into estate values("fnaqi3flanv","estate","faknfakndfa");
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create table access(ac_id int primary key auto_increment,es_id varchar(100),ro_id varchar(100),st_id varchar(100),during int);
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insert into access(es_id,ro_id,st_id,during) values("fnaqi3flanv","aknfdfadn","fadkfakdnfadfn",3),
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("fnaqi3flanv","kdfnakdnfakndfajfajdb","nfwiha4hqwkefnjg",19);
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create table room(rm_id varchar(100) primary key,es_id varchar(100),floor int,rent int,is_taken tinyint);
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insert into room values("asdfghjklsdfghjkl","fnaqi3flanv",3,120000,0)
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```
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- 検索
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```SQL
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select es.* from estate as es
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inner join room as rm on es.es_id=rm.es_id and rm.rent>=100000
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and rm.es_id in (
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select es_id from access as ac where ac.st_id in(
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select st_id from station as st
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inner join route as ro on st.ro_id=ro.ro_id and ro.ro_name='山手線'
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and st.st_name in('渋谷駅','恵比寿駅')
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)
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)
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86
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87
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```
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