回答編集履歴
3
追記
answer
CHANGED
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@@ -4,4 +4,13 @@
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|
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4
4
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WHERE L.`waza_id` IN (3, 4)
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5
5
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GROUP BY M.id
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6
6
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HAVING count(L.`waza_id`) = 2;
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7
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+
```
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8
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+
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9
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+
### 前提条件が変わったので
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10
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+
```sql
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11
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+
SELECT M.* FROM monsters M
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12
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+
INNER JOIN learn L ON M.`id` = L.`monster_id`
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13
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+
WHERE L.`waza_id` IN (3, 4)
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14
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+
GROUP BY M.id
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15
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+
HAVING count(distinct L.`waza_id`) = 2;
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7
16
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```
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2
修正
answer
CHANGED
|
@@ -1,5 +1,5 @@
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|
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1
1
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```sql
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2
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-
SELECT M.*
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2
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+
SELECT M.* FROM monsters M
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3
3
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INNER JOIN learn L ON M.`id` = L.`monster_id`
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4
4
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WHERE L.`waza_id` IN (3, 4)
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5
5
|
GROUP BY M.id
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1
追記
answer
CHANGED
|
@@ -1,5 +1,7 @@
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|
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1
1
|
```sql
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2
|
-
SELECT M.* FROM monsters M
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2
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+
SELECT M.*, count(L.`waza_id`) FROM monsters M
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3
3
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INNER JOIN learn L ON M.`id` = L.`monster_id`
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4
|
-
WHERE L.`waza_id` IN (
|
|
4
|
+
WHERE L.`waza_id` IN (3, 4)
|
|
5
|
+
GROUP BY M.id
|
|
6
|
+
HAVING count(L.`waza_id`) = 2;
|
|
5
7
|
```
|