回答編集履歴
3
想定仕様に説明を追記
test
CHANGED
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@@ -8,11 +8,16 @@
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|0001|100|0|
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|0001|0|10|
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11
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- 同じ社員番号で複数レコードが存在する
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- 給料および手当には、「正しい値」「空白」「０」のいずれかが入っている
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+
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**OUTPUT（ディクショナリ）**
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|社員番号|給料|手当|
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16
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|:--:|:--:|:--:|
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|0001|100|10|
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- 社員番号で重複したデータを取り除き一意となった結果を出力
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- 一意にする際、給料および手当は「正しい値」を採用
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---
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```VBA
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Sub sample()
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2
想定する仕様について追記
test
CHANGED
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@@ -1,3 +1,19 @@
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1
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やりたいことが以下のような仕様だと想像し、その想定のもとでコードを記述しました。
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3
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**INPUT（ファイル）**
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|社員番号|給料|手当|
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5
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|:--:|:--:|:--:|
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|0001|100||
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7
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|0001| |10|
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8
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|0001|100|0|
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|0001|0|10|
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10
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**OUTPUT（ディクショナリ）**
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|社員番号|給料|手当|
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13
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|:--:|:--:|:--:|
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14
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|0001|100|10|
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15
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---
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1
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```VBA
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Sub sample()
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Open ファイル名 For Input As #1
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1
teate, kyu 空白対応 他
test
CHANGED
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@@ -1,28 +1,46 @@
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1
1
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```VBA
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-
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Sub sample()
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-
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Open ファイル名 For Input As #1
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4
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Dim dic As Object
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Set dic = CreateObject("Scripting.Dictionary")
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7
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-
Dim buf As Variant
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8
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Dim buf As Variant
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Dim tmp As Variant
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Dim tmp As Variant
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Dim employeeNum As String
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Dim employeeNum As String
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8
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Dim teate As Long
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Dim teate As Long
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-
Dim kyu As Long
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Dim kyu As Long
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Line Input #1, buf
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Line Input #1, buf
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Line Input #1, buf
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Line Input #1, buf
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Do Until EOF(1)
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Line Input #1, buf
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tmp = Split(buf, ",")
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employeeNum = tmp(11)
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teate = Val(tmp(45))
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kyu = Val(tmp(40))
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If dic.Exists(employeeNum) Then
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If teate = 0 Then teate = dic(employeeNum)(1)
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If kyu = 0 Then kyu = dic(employeeNum)(2)
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End If
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dic(employeeNum) = Array(employeeNum, teate, kyu)
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Loop
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Close #1
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Dim k, v
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For Each k In dic.Keys
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40
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v = dic(k)
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11
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-
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Debug.Print k, Join(v, vbTab)
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Next
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-
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End Sub
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-
Line Input #1, buf
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Line Input #1, buf
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45
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Do Until EOF(1)
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Line Input #1, buf
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tmp = Split(buf, ",")
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employeeNum = tmp(11)
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teate = tmp(45)
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kyu = tmp(40)
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If dic.Exists(employeeNum) Then
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If teate = 0 Then teate = dic(employeeNum)(1)
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If kyu = 0 Then kyu = dic(employeeNum)(2)
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End If
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dic(employeeNum) = Array(employeeNum, teate, kyu)
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Loop
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46
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```
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