回答編集履歴
1
推敲
answer
CHANGED
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@@ -11,4 +11,5 @@
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11
11
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and char_length(Name)=(
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12
12
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select min(char_length(Name)) from User
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13
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WHERE Name LIKE '%a%c%u%'
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14
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-
)
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14
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+
)
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15
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+
```
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